marandapyatt13 marandapyatt13

01-05-2018
Mathematics

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Simplify Completely

√27y^{8}

PLEASE HELP!!!

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Аноним Аноним

01-05-2018

[tex] \sqrt{ {27y}^{8} } = 3 {y}^{4} \sqrt{3} [/tex]

Hope this helps. - M

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