HotaroKim
HotaroKim HotaroKim
  • 02-03-2020
  • Physics
contestada

A lightbulb consumed 1100J in 30 minutes. Find Power, resistance, and calculate energy in kWh

Respuesta :

MathPhys
MathPhys MathPhys
  • 02-03-2020

Explanation:

30 minutes is 1800 seconds.

Power = energy / time

P = 1100 J / 1800 s

P = 0.611 W

Converting the energy from J to kWh:

1100 J × (1 Ws / 1 J) × (1 kW / 1000 W) × (1 h / 3600 s) = 3.06×10⁻⁴ kWh

To find resistance, you need to be given either the voltage or the current.

Answer Link

Otras preguntas

Is 4xy + 2y = 9 linear ? If yes write the equation in standard form & determine the x & y interests
In class 6, 80percent of the children like crisps. 75percent of the children who like crisps also like chocolate. In class 6 what percentage of the children lik
How is the graph of y=-8x^2-2 diffrent from the graph of y=-8x^2
Why is India considered a subcontinent
express each number in fraction form before finding the inverse:7,10,1 3/4,
Stem-and-Leaf Plots question: How many swimmers were younger then 30 Stem -- Leaf 0 1-- 1 2-- 3,9 3 --
Trent and Chris are musicians, and they recently played a concert for 20,000 fans. The rectangular venue measured 87 yards by 57 yards. What was the approximate
how can temperature can affect communication?
A basketball player achieves a hang time of 0.773 s in dunking the ball. What vertical height will he attain? The acceleration of gravity is 9.8 m/s^2 .
Prove that 2n + 1 ≤ 2n for n ≥ 3